(2x/6x^2-5x-6)-(10/8x^2-14x+3)=(19x/12x^2-5x-2)

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Solution for (2x/6x^2-5x-6)-(10/8x^2-14x+3)=(19x/12x^2-5x-2) equation: 



(2x/6x^2-5x-6)-(10/8x^2-14x+3)=(19x/12x^2-5x-2)

We move all terms to the left:

(2x/6x^2-5x-6)-(10/8x^2-14x+3)-((19x/12x^2-5x-2))=0



Domain of the equation: 6x^2-5x-6)!=0

x∈R





Domain of the equation: 8x^2-14x+3)!=0

x∈R





Domain of the equation: 12x^2-5x-2))!=0

x∈R



We get rid of parentheses

2x/6x^2-5x-10/8x^2+14x-((19x/12x^2-5x-2))-6-3=0

We calculate fractions

We do not support expression: x^6

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